Animesh has N empty candy jars numbered from 1 to N with infinite capacity. He performs M operations. Each operation is described by 3 integers a, b and k where a and b are index of the jars and k is the number of candies to be added inside each jar with index between a and b (both inclusive). Can you tell the average number of candies after M operations?
Input Format
The first line contains two integers N and M separated by a single space.
M lines follow. Each of the M lines contain three integers a, b and k separated by single space.
The first line contains two integers N and M separated by a single space.
M lines follow. Each of the M lines contain three integers a, b and k separated by single space.
Output Format
A single line containing the average number of candies across N jars, rounded down to the nearest integer.
A single line containing the average number of candies across N jars, rounded down to the nearest integer.
Constraints
3 <= N <= 107
1 <= M <= 105
1 <= a <= b <= N
0 <= k <= 106
3 <= N <= 107
1 <= M <= 105
1 <= a <= b <= N
0 <= k <= 106
Sample Input #00
5 3
1 2 100
2 5 100
3 4 100
Sample Output #00
160
Explanation
Initially each of the jar contains 0 candies
Initially each of the jar contains 0 candies
0 0 0 0 0
First operation
100 100 0 0 0
Second operation
100 200 100 100 100
Third operation
100 200 200 200 100
Total = 800, Average = 800/5 = 160
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int main() {
int i,j;
long int N,M,a,b,k,sum=0,c;
scanf("%ld %ld",&N,&M);
for(i=1;i<=M;i++)
{
scanf("%ld %ld %ld",&a,&b,&k);
c=b-a+1;
c=c*k;
sum=sum+c;
}
sum/=N;
printf("%ld",sum);
return 0;
}
Thanks for ruining this for people who actually try to use these as interview questions
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